Let {G = (G,+)} be an abelian countable discrete group. A measure-preserving {G}-system {X = (X, {\mathcal X}, \mu, (T_g)_{g \in G})} (or {G}-system for short) is a probability space {(X, {\mathcal X}, \mu)}, equipped with a measure-preserving action {T_g: X \rightarrow X} of the group {G}, thus

\displaystyle  \mu( T_g(E) ) = \mu(E)

for all {E \in {\mathcal X}} and {g \in G}, and

\displaystyle  T_g T_h = T_{g+h}

for all {g, h \in G}, with {T_0} equal to the identity map. Classically, ergodic theory has focused on the cyclic case {G={\bf Z}} (in which the {T_g} are iterates of a single map {T = T_1}, with elements of {G} being interpreted as a time parameter), but one can certainly consider actions of other groups {G} also (including continuous or non-abelian groups).

A {G}-system is said to be strongly {2}-mixing, or strongly mixing for short, if one has

\displaystyle  \lim_{g \rightarrow \infty} \mu( A \cap T_g B ) = \mu(A) \mu(B)

for all {A, B \in {\mathcal X}}, where the convergence is with respect to the one-point compactification of {G} (thus, for every {\epsilon > 0}, there exists a compact (hence finite) subset {K} of {G} such that {|\mu(A \cap T_g B) - \mu(A)\mu(B)| \leq \epsilon} for all {g \not \in K}).

Similarly, we say that a {G}-system is strongly {3}-mixing if one has

\displaystyle  \lim_{g,h,h-g \rightarrow \infty} \mu( A \cap T_g B \cap T_h C ) = \mu(A) \mu(B) \mu(C)

for all {A,B,C \in {\mathcal X}}, thus for every {\epsilon > 0}, there exists a finite subset {K} of {G} such that

\displaystyle  |\mu( A \cap T_g B \cap T_h C ) - \mu(A) \mu(B) \mu(C)| \leq \epsilon

whenever {g, h, h-g} all lie outside {K}.

It is obvious that a strongly {3}-mixing system is necessarily strong {2}-mixing. In the case of {{\bf Z}}-systems, it has been an open problem for some time, due to Rohlin, whether the converse is true:

Problem 1 (Rohlin’s problem) Is every strongly mixing {{\bf Z}}-system necessarily strongly {3}-mixing?

This is a surprisingly difficult problem. In the positive direction, a routine application of the Cauchy-Schwarz inequality (via van der Corput’s inequality) shows that every strongly mixing system is weakly {3}-mixing, which roughly speaking means that {\mu(A \cap T_g B \cap T_h C)} converges to {\mu(A) \mu(B) \mu(C)} for most {g, h \in {\bf Z}}. Indeed, every weakly mixing system is in fact weakly mixing of all orders; see for instance this blog post of Carlos Matheus, or these lecture notes of myself. So the problem is to exclude the possibility of correlation between {A}, {T_g B}, and {T_h C} for a small but non-trivial number of pairs {(g,h)}.

It is also known that the answer to Rohlin’s problem is affirmative for rank one transformations (a result of Kalikow) and for shifts with purely singular continuous spectrum (a result of Host; note that strongly mixing systems cannot have any non-trivial point spectrum). Indeed, any counterexample to the problem, if it exists, is likely to be highly pathological.

In the other direction, Rohlin’s problem is known to have a negative answer for {{\bf Z}^2}-systems, by a well-known counterexample of Ledrappier which can be described as follows. One can view a {{\bf Z}^2}-system as being essentially equivalent to a stationary process {(x_{n,m})_{(n,m) \in {\bf Z}^2}} of random variables {x_{n,m}} in some range space {\Omega} indexed by {{\bf Z}^2}, with {X} being {\Omega^{{\bf Z}^2}} with the obvious shift map

\displaystyle  T_{(g,h)} (x_{n,m})_{(n,m) \in {\bf Z}^2} := (x_{n-g,m-h})_{(n,m) \in {\bf Z}^2}.

In Ledrappier’s example, the {x_{n,m}} take values in the finite field {{\bf F}_2} of two elements, and are selected at uniformly random subject to the “Pascal’s triangle” linear constraints

\displaystyle  x_{n,m} = x_{n-1,m} + x_{n,m-1}.

A routine application of the Kolmogorov extension theorem allows one to build such a process. The point is that due to the properties of Pascal’s triangle modulo {2} (known as Sierpinski’s triangle), one has

\displaystyle  x_{n,m} = x_{n-2^k,m} + x_{n,m-2^k}

for all powers of two {2^k}. This is enough to destroy strong {3}-mixing, because it shows a strong correlation between {x}, {T_{(2^k,0)} x}, and {T_{(0,2^k)} x} for arbitrarily large {k} and randomly chosen {x \in X}. On the other hand, one can still show that {x} and {T_g x} are asymptotically uncorrelated for large {g}, giving strong {2}-mixing. Unfortunately, there are significant obstructions to converting Ledrappier’s example from a {{\bf Z}^2}-system to a {{\bf Z}}-system, as pointed out by de la Rue.

In this post, I would like to record a “finite field” variant of Ledrappier’s construction, in which {{\bf Z}^2} is replaced by the function field ring {{\bf F}_3[t]}, which is a “dyadic” (or more precisely, “triadic”) model for the integers (cf. this earlier blog post of mine). In other words:

Theorem 2 There exists a {{\bf F}_3[t]}-system that is strongly {2}-mixing but not strongly {3}-mixing.

The idea is much the same as that of Ledrappier; one builds a stationary {{\bf F}_3[t]}-process {(x_n)_{n \in {\bf F}_3[t]}} in which {x_n \in {\bf F}_3} are chosen uniformly at random subject to the constraints

\displaystyle  x_n + x_{n + t^k} + x_{n + 2t^k} = 0 \ \ \ \ \ (1)

for all {n \in {\bf F}_3[t]} and all {k \geq 0}. Again, this system is manifestly not strongly {3}-mixing, but can be shown to be strongly {2}-mixing; I give details below the fold.

As I discussed in this previous post, in many cases the dyadic model serves as a good guide for the non-dyadic model. However, in this case there is a curious rigidity phenomenon that seems to prevent Ledrappier-type examples from being transferable to the one-dimensional non-dyadic setting; once one restores the Archimedean nature of the underlying group, the constraints (1) not only reinforce each other strongly, but also force so much linearity on the system that one loses the strong mixing property.

— 1. The example —

Let {B} be any ball in {{\bf F}_3[t]}, i.e. any set of the form {\{ n \in {\bf F}_3[t]: \hbox{deg}(n-n_0) \leq K \}} for some {n_0 \in {\bf F}_3[t]} and {K \geq 0}. One can then create a process {x_B = (x_n)_{n \in B}} adapted to this ball, by declaring {(x_n)_{n \in B}} to be uniformly distributed in the vector space {V_B \leq {\bf F}_3^B} of all tuples with coefficients in {{\bf F}_3} that obey (1) for all {n \in B} and {k \leq K}. Because any translate of a line {(n,n+t^k,n+t^{2k})} is still a line, we see that this process is stationary with respect to all shifts {n \mapsto n+g} of degree {\hbox{deg}(g)} at most {K}. Also, if {B \subset B'} are nested balls, we see that the vector space {V_{B'}} projects surjectively via the restriction map to {V_B} (since any tuple obeying (1) in {B} can be extended periodically to one obeying (1) in {B'}). As such, we see that the process {x_B} is equivalent in distribution to the restriction {x_{B'}\downharpoonright_B} of {x_{B'}} to {B}. Applying the Kolmogorov extension theorem, we conclude that there exists an infinite process {x = (x_n)_{n \in {\bf F}_3[t]}} whose restriction {x \downharpoonright_B} to any ball {B} has the distribution of {x_B}. As each {x_B} was stationary with respect to translations that preserved {B}, we see that the full process {x} is stationary with respect to the entire group {{\bf F}_3[t]}.

Now let {B} be a ball

\displaystyle B := \{ n \in {\bf F}_3[t]: \hbox{deg}(n-n_0) \leq K \},

which we divide into three equally sized sub-balls {B_0, B_1, B_2} by the formula

\displaystyle B_i := \{ n \in {\bf F}_3[t]: \hbox{deg}(n-(n_0+it^K)) \leq K-1 \}.

By construction, we see that

\displaystyle  V_B = \{ ( x_{B_0}, x_{B_1}, x_{B_2} ): x_{B_0}, x_{B_1}, x_{B_2} \in V_{B_0}; x_{B_0}+x_{B_1}+x_{B_2} = 0 \}

where we use translation by {t^K} to identify {V_{B_0}}, {V_{B_1}}, and {V_{B_2}} together. As a consequence, we see that the projection map {(x_{B_0}, x_{B_1}, x_{B_2}) \rightarrow (x_{B_0}, x_{B_1})} from {V_B} to {V_{B_0} \times V_{B_0}} is surjective, and this implies that the random variables {x\downharpoonright_{B_0}, x\downharpoonright_{B_1}} are independent. More generally, this argument implies that for any disjoint balls {B, B'}, the random variables {x\downharpoonright_B} and {x\downharpoonright_{B'}} are independent.

Now we can prove strong {2}-mixing. Given any measurable event {A} and any {\epsilon > 0}, one can find a ball {B} and a set {A'} depending only on {x\downharpoonright_B} such that {A} and {A'} differ by at most {\epsilon} in measure. On the other hand, for {g} outside of {B-B}, {A'} and {T_g A'} are determined by the restrictions of {x} to disjoint balls and are thus independent. In particular,

\displaystyle  \mu( A' \cap T_g A' ) = \mu(A')^2

and thus

\displaystyle  \mu( A \cap T_g A ) = \mu(A)^2 + O(\epsilon)

which gives strong {2}-mixing.

On the other hand, we have {x_0 + x_{t^k} + x_{2t^k} = 0} almost surely, while each {x_0, x_{t^k}, x_{2t^k}} are uniformly distributed in {{\bf F}_3} and pairwise independent. In particular, if {E} is the event that {x_0=0}, we see that

\displaystyle  \mu( E ) = 1/3

and

\displaystyle  \mu( E \cap T_{t^k} E \cap T_{t^{2k}} E ) = 1/9

showing that strong {3}-mixing fails.

Remark 1 In the Archimedean case {G = {\bf Z}}, a constraint such as {x_n + x_{n+1} + x_{n+2} = 0} propagates itself to force complete linearity of {x_n}, which is highly incompatible with strong mixing; in contrast, in the non-Archimedean case {G = {\bf F}_3}, such a constraint does not propagate very far. It is then tempting to relax this constraint, for instance by adopting an Ising-type model which penalises a configuration whenever quantities such as {x_n + x_{n+1} + x_{n+2}} deviates from zero. However, to destroy strong {3}-mixing, one needs infinitely many such penalisation terms, which roughly corresponds to an Ising model in an infinite-dimensional lattice. In such models, it seems difficult to find a way to set the “temperature” parameters in such a way that one has meaningful {3}-correlations, without the system “freezing up” so much that {2}-mixing fails. It is also tempting to try to truncate the constraints such as (1) to prevent their propagation, but it seems that any naive attempt to perform a truncation either breaks stationarity, or introduces enough periodicity into the system that {2}-mixing breaks down. My tentative opinion on this problem is that a {{\bf Z}}-counterexample is constructible, but one would have to use a very delicate and finely tuned construction to achieve it.