difference $ X-P_ {i} $

and taking into account the

$ \ beta (x) = O \ left (\ frac {x} {\ ln ^ M x} \ right) $ – even among those who can not be branded

as the sum of two prime numbers, it follows that one of the differences

$ X-P_ {i} = P_ {k} + P_ {j} $,

$ X = P_ {i} + P_ {k} + P_ {j} $.

We chose $ x $ and got Vinogradov theorem …

To answer this Tao?:

]]>require Endorsement needed for math.NT, you would not have helped me?

Я доказал Гипотезу Лежандра , хотел послать в arxiv.org, но там

требуют Endorsement needed for math.NT, Вы бы мне не помогли ?

You can become next Newton, Gauss or Archimedes. Or you became.

The world salute to you. All the best.

Sunil Kumar Kashyap

]]>I want to know if anyone can recommend a program to write and compile a latex and ArXiv? ]]>