A few years ago, Ben Green, Tamar Ziegler, and myself proved the following (rather technical-looking) inverse theorem for the Gowers norms:
Theorem 1 (Discrete inverse theorem for Gowers norms) Let
and
be integers, and let
. Suppose that
is a function supported on
such that
Then there exists a filtered nilmanifold
of degree
and complexity
, a polynomial sequence
, and a Lipschitz function
of Lipschitz constant
such that
For the definitions of “filtered nilmanifold”, “degree”, “complexity”, and “polynomial sequence”, see the paper of Ben, Tammy, and myself. (I should caution the reader that this blog post will presume a fair amount of familiarity with this subfield of additive combinatorics.) This result has a number of applications, for instance to establishing asymptotics for linear equations in the primes, but this will not be the focus of discussion here.
The purpose of this post is to record the observation that this “discrete” inverse theorem, together with an equidistribution theorem for nilsequences that Ben and I worked out in a separate paper, implies a continuous version:
Theorem 2 (Continuous inverse theorem for Gowers norms) Let
be an integer, and let
. Suppose that
is a measurable function supported on
such that
Then there exists a filtered nilmanifold
of degree
and complexity
, a (smooth) polynomial sequence
, and a Lipschitz function
of Lipschitz constant
such that
The interval can be easily replaced with any other fixed interval by a change of variables. A key point here is that the bounds are completely uniform in the choice of
. Note though that the coefficients of
can be arbitrarily large (and this is necessary, as can be seen just by considering functions of the form
for some arbitrarily large frequency
).
It is likely that one could prove Theorem 2 by carefully going through the proof of Theorem 1 and replacing all instances of with
(and making appropriate modifications to the argument to accommodate this). However, the proof of Theorem 1 is quite lengthy. Here, we shall proceed by the usual limiting process of viewing the continuous interval
as a limit of the discrete interval
as
. However there will be some problems taking the limit due to a failure of compactness, and specifically with regards to the coefficients of the polynomial sequence
produced by Theorem 1, after normalising these coefficients by
. Fortunately, a factorisation theorem from a paper of Ben Green and myself resolves this problem by splitting
into a “smooth” part which does enjoy good compactness properties, as well as “totally equidistributed” and “periodic” parts which can be eliminated using the measurability (and thus, approximate smoothness), of
.
We now prove Theorem 2. Firstly observe from Hölder’s inequality that the Gowers norm expression in the left-hand side of (1) is continuous in in the
topology. As such, it suffices to prove the theorem for a dense class of
, such as the Lipschitz-continuous
, so long as the bounds remain uniform in
. Thus, we may assume without loss of generality that
is Lipschitz continuous.
Now let be a large integer (which will eventually be sent to infinity along a subsequence). As
is Lipschitz continuous, the integral in (1) is certainly Riemann integrable, and so for sufficiently large
(where we allow “sufficiently large” to depend on the Lipschitz constant) we will have
(say). Applying Theorem 2, we can thus find for sufficiently large , a filtered nilmanifold
of degree
and complexity
, a polynomial sequence
, and a Lipschitz function
of Lipschitz constant
such that
Now we prepare to take limits as , passing to subsequences as necessary. Using Mal’cev bases, one can easily check that there are only finitely many filtered nilmanifolds
of a fixed degree and complexity, hence by passing to a subsequence of
we may assume that
is independent of
. The Lipschitz functions
are now equicontinuous on a fixed compact domain
, so by the Arzelá-Ascoli theorem and further passage to a subsequence we may assume that
converges uniformly to a Lipschitz function
of Lipschitz constant
. In particular (passing to a further subsequence as necessary) we have
We have removed a lot of the dependencies of the nilsequence on
, however there is still a serious lack of compactness in the remaining dependency of the polynomial sequence
on
. Fortunately, we can argue as follows. Let
be large quantities (depending on
, and the Lipschitz constant of
) to be chosen later. Applying the factorisation theorem for polynomial sequences (see Theorem 1.19 of this paper of Ben Green and myself), we may find for each
in the current subsequence, an integer
, a rational subgroup
of
whose associated filtered nilmanifold
has structure constants that are
-rational with respect to the Mal’cev bais of
, and a decomposition
where
-
is a polynomial sequence which is
-smooth;
-
is a polynomial sequence with
is totally
-equidistributed in
; and
-
is a polynomial sequence which is
-rational, and
is periodic with period at most
.
See the above referenced paper for a definition of all the terminology used here.
Once again we can make a lot of the data here independent of by passing to a subsequence. Firstly,
takes only finitely many values so by passing to a subsequence we may assume that
is independent of
. Then the number of rational subgroups
with
-rational structure constants is also finite, so by passing to a further subsequence we may take
independent of
, so
is also independent of
. Up to right multiplication by polynomial sequences from
to
(which do not affect the value of
), there are only finitely many
-rational polynomial sequences
that are periodic with period at most
, so we may take
independent of
. Finally, using coordinates one can write
where
is a continuous polynomial sequence whose coefficients are bounded uniformly in
. By Bolzano-Weierstrass, we may assume on passing to a subsequence that
converges locally uniformly to a limit
, which is again a continuous polynomial sequence. Thus, on passing to a further subsequence, we have
Let be the period of
. By the pigeonhole principle (and again passing to a subsequence) we may find a residue class
independent of
such that
Because is totally
-equidistributed in
, and
is
-rational, the conjugate
is totally
-equidistributed in
, where
and
; see Section 2 of this paper of Ben and myself for a derivation of this fact. From this, we have the approximation
for any and any fixed interval
, where
is the length of
and the integral is with respect to Haar measure, and
are sufficiently large depending on
. Using Riemann integration, we thus see that the left-hand side of (2) is thus of the form
for sufficiently large if
are sufficiently large depending on
, and the Lipschitz constant of
, and so (writing
) we have
if are sufficiently large depending on
, and the Lipschitz constant of
. If we let
be a continuous polynomial sequence that is equidistributed in
(which will happen as soon as the sequence is equidistributed with respect to the abelianisation of
, by an old result of Leon Green), then a similar argument shows that
and thus there exists such that
Setting , we obtain the claim.
I thank Ben Green for helpful conversations that inspired this post.
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23 July, 2015 at 7:33 pm
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29 July, 2015 at 4:49 am
Arkadeep Mukhopadhyay
I am sure I am viewing a blog written by a true author. I love physics and maths greatly although i am a medical student.Till now I have read only two posts but I can assure you that within few days I’ll increase the tally exponentially!
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