You are currently browsing the tag archive for the ‘Coulomb gauge’ tag.

I was pleased to learn this week that the 2019 Abel Prize was awarded to Karen Uhlenbeck. Uhlenbeck laid much of the foundations of modern geometric PDE. One of the few papers I have in this area is in fact a joint paper with Gang Tian extending a famous singularity removal theorem of Uhlenbeck for four-dimensional Yang-Mills connections to higher dimensions. In both these papers, it is crucial to be able to construct “Coulomb gauges” for various connections, and there is a clever trick of Uhlenbeck for doing so, introduced in another important paper of hers, which is absolutely critical in my own paper with Tian. Nowadays it would be considered a standard technique, but it was definitely not so at the time that Uhlenbeck introduced it.

Suppose one has a smooth connection ${A}$ on a (closed) unit ball ${B(0,1)}$ in ${{\bf R}^n}$ for some ${n \geq 1}$, taking values in some Lie algebra ${{\mathfrak g}}$ associated to a compact Lie group ${G}$. This connection then has a curvature ${F(A)}$, defined in coordinates by the usual formula

$\displaystyle F(A)_{\alpha \beta} = \partial_\alpha A_\beta - \partial_\beta A_\alpha + [A_\alpha,A_\beta]. \ \ \ \ \ (1)$

It is natural to place the curvature in a scale-invariant space such as ${L^{n/2}(B(0,1))}$, and then the natural space for the connection would be the Sobolev space ${W^{n/2,1}(B(0,1))}$. It is easy to see from (1) and Sobolev embedding that if ${A}$ is bounded in ${W^{n/2,1}(B(0,1))}$, then ${F(A)}$ will be bounded in ${L^{n/2}(B(0,1))}$. One can then ask the converse question: if ${F(A)}$ is bounded in ${L^{n/2}(B(0,1))}$, is ${A}$ bounded in ${W^{n/2,1}(B(0,1))}$? This can be viewed as asking whether the curvature equation (1) enjoys “elliptic regularity”.

There is a basic obstruction provided by gauge invariance. For any smooth gauge ${U: B(0,1) \rightarrow G}$ taking values in the Lie group, one can gauge transform ${A}$ to

$\displaystyle A^U_\alpha := U^{-1} \partial_\alpha U + U^{-1} A_\alpha U$

and then a brief calculation shows that the curvature is conjugated to

$\displaystyle F(A^U)_{\alpha \beta} = U^{-1} F_{\alpha \beta} U.$

This gauge symmetry does not affect the ${L^{n/2}(B(0,1))}$ norm of the curvature tensor ${F(A)}$, but can make the connection ${A}$ extremely large in ${W^{n/2,1}(B(0,1))}$, since there is no control on how wildly ${U}$ can oscillate in space.

However, one can hope to overcome this problem by gauge fixing: perhaps if ${F(A)}$ is bounded in ${L^{n/2}(B(0,1))}$, then one can make ${A}$ bounded in ${W^{n/2,1}(B(0,1))}$ after applying a gauge transformation. The basic and useful result of Uhlenbeck is that this can be done if the ${L^{n/2}}$ norm of ${F(A)}$ is sufficiently small (and then the conclusion is that ${A}$ is small in ${W^{n/2,1}}$). (For large connections there is a serious issue related to the Gribov ambiguity.) In my (much) later paper with Tian, we adapted this argument, replacing Lebesgue spaces by Morrey space counterparts. (This result was also independently obtained at about the same time by Meyer and Riviére.)

To make the problem elliptic, one can try to impose the Coulomb gauge condition

$\displaystyle \partial^\alpha A_\alpha = 0 \ \ \ \ \ (2)$

(also known as the Lorenz gauge or Hodge gauge in various papers), together with a natural boundary condition on ${\partial B(0,1)}$ that will not be discussed further here. This turns (1), (2) into a divergence-curl system that is elliptic at the linear level at least. Indeed if one takes the divergence of (1) using (2) one sees that

$\displaystyle \partial^\alpha F(A)_{\alpha \beta} = \Delta A_\beta + \partial^\alpha [A_\alpha,A_\beta] \ \ \ \ \ (3)$

and if one could somehow ignore the nonlinear term ${\partial^\alpha [A_\alpha,A_\beta]}$ then we would get the required regularity on ${A}$ by standard elliptic regularity estimates.

The problem is then how to handle the nonlinear term. If we already knew that ${A}$ was small in the right norm ${W^{n/2,1}(B(0,1))}$ then one can use Sobolev embedding, Hölder’s inequality, and elliptic regularity to show that the second term in (3) is small compared to the first term, and so one could then hope to eliminate it by perturbative analysis. However, proving that ${A}$ is small in this norm is exactly what we are trying to prove! So this approach seems circular.

Uhlenbeck’s clever way out of this circularity is a textbook example of what is now known as a “continuity” argument. Instead of trying to work just with the original connection ${A}$, one works with the rescaled connections ${A^{(t)}_\alpha(x) := t A_\alpha(tx)}$ for ${0 \leq t \leq 1}$, with associated rescaled curvatures ${F(A^{(t)})_\alpha = t^2 F(A)_{\alpha \beta}(tx)}$. If the original curvature ${F(A)}$ is small in ${L^{n/2}}$ norm (e.g. bounded by some small ${\varepsilon>0}$), then so are all the rescaled curvatures ${F(A^{(t)})}$. We want to obtain a Coulomb gauge at time ${t=1}$; this is difficult to do directly, but it is trivial to obtain a Coulomb gauge at time ${t=0}$, because the connection vanishes at this time. On the other hand, once one has successfully obtained a Coulomb gauge at some time ${t \in [0,1]}$ with ${A^{(t)}}$ small in the natural norm ${W^{n/2,1}}$ (say bounded by ${C \varepsilon}$ for some constant ${C}$ which is large in absolute terms, but not so large compared with say ${1/\varepsilon}$), the perturbative argument mentioned earlier (combined with the qualitative hypothesis that ${A}$ is smooth) actually works to show that a Coulomb gauge can also be constructed and be small for all sufficiently close nearby times ${t' \in [0,1]}$ to ${t}$; furthermore, the perturbative analysis actually shows that the nearby gauges enjoy a slightly better bound on the ${W^{n/2,1}}$ norm, say ${C\varepsilon/2}$ rather than ${C\varepsilon}$. As a consequence of this, the set of times ${t}$ for which one has a good Coulomb gauge obeying the claimed estimates is both open and closed in ${[0,1]}$, and also contains ${t=0}$. Since the unit interval ${[0,1]}$ is connected, it must then also contain ${t=1}$. This concludes the proof.

One of the lessons I drew from this example is to not be deterred (especially in PDE) by an argument seeming to be circular; if the argument is still sufficiently “nontrivial” in nature, it can often be modified into a usefully non-circular argument that achieves what one wants (possibly under an additional qualitative hypothesis, such as a continuity or smoothness hypothesis).