A fundamental characteristic of many mathematical spaces (e.g. vector spaces, metric spaces, topological spaces, etc.) is their *dimension*, which measures the “complexity” or “degrees of freedom” inherent in the space. There is no single notion of dimension; instead, there are a variety of different versions of this concept, with different versions being suitable for different classes of mathematical spaces. Typically, a single mathematical object may have several subtly different notions of dimension that one can place on it, which will be related to each other, and which will often agree with each other in “non-pathological” cases, but can also deviate from each other in many other situations. For instance:

- One can define the dimension of a space by seeing how it compares to some standard reference spaces, such as or ; one may view a space as having dimension if it can be (locally or globally) identified with a standard -dimensional space. The dimension of a vector space or a manifold can be defined in this fashion.
- Another way to define dimension of a space is as the largest number of “independent” objects one can place inside that space; this can be used to give an alternate notion of dimension for a vector space, or of an algebraic variety, as well as the closely related notion of the transcendence degree of a field. The concept of VC dimension in machine learning also broadly falls into this category.
- One can also try to define dimension inductively, for instance declaring a space to be -dimensional if it can be “separated” somehow by an -dimensional object; thus an -dimensional object will tend to have “maximal chains” of sub-objects of length (or , depending on how one initialises the chain and how one defines length). This can give a notion of dimension for a topological space or a commutative ring.

The notions of dimension as defined above tend to necessarily take values in the natural numbers (or the cardinal numbers); there is no such space as , for instance, nor can one talk about a basis consisting of linearly independent elements, or a chain of maximal ideals of length . There is however a somewhat different approach to the concept of dimension which makes no distinction between integer and non-integer dimensions, and is suitable for studying “rough” sets such as fractals. The starting point is to observe that in the -dimensional space , the volume of a ball of radius grows like , thus giving the following heuristic relationship

between volume, scale, and dimension. Formalising this heuristic leads to a number of useful notions of dimension for subsets of (or more generally, for metric spaces), including (upper and lower) Minkowski dimension (also known as box-packing dimension or Minkowski-Bougliand dimension), and Hausdorff dimension.

[In -theory, it is also convenient to work with “virtual” vector spaces or vector bundles, such as formal differences of such spaces, and which may therefore have a negative dimension; but as far as I am aware there is no connection between this notion of dimension and the metric ones given here.]

Minkowski dimension can either be defined externally (relating the external volume of -neighbourhoods of a set to the scale ) or internally (relating the internal -entropy of to the scale). Hausdorff dimension is defined internally by first introducing the -dimensional *Hausdorff measure* of a set for any parameter , which generalises the familiar notions of length, area, and volume to non-integer dimensions, or to rough sets, and is of interest in its own right. Hausdorff dimension has a lengthier definition than its Minkowski counterpart, but is more robust with respect to operations such as countable unions, and is generally accepted as the “standard" notion of dimension in metric spaces. We will compare these concepts against each other later in these notes.

One use of the notion of dimension is to create finer distinctions between various types of “small" subsets of spaces such as , beyond what can be achieved by the usual Lebesgue measure (or Baire category). For instance, a point, line, and plane in all have zero measure with respect to three-dimensional Lebesgue measure (and are nowhere dense), but of course have different dimensions (, , and respectively). (The Kakeya set conjecture, discussed recently on this blog, offers another good example.) This can be used to clarify the nature of various singularities, such as that arising from non-smooth solutions to PDE; a function which is non-smooth on a set of large Hausdorff dimension can be considered less smooth than one which is non-smooth on a set of small Hausdorff dimension, even if both are smooth almost everywhere. While many properties of the singular set of such a function are worth studying (e.g. their rectifiability), understanding their dimension is often an important starting point. The interplay between these types of concepts is the subject of geometric measure theory.

** — 1. Minkowski dimension — **

Before we study the more standard notion of Hausdorff dimension, we begin with the more elementary concept of the (upper and lower) Minkowski dimension of a subset of a Euclidean space .

There are several equivalent ways to approach Minkowski dimension. We begin with an “external” approach, based on a study of the -neighbourhoods of , where and we use the Euclidean metric on . These are open sets in and therefore have a -dimensional volume (or Lebesgue measure) . To avoid divergences, let us assume for now that is bounded, so that the have finite volume.

Let . Suppose is a bounded portion of a -dimensional subspace, e.g. , where is the unit ball in and we identify with in the usual manner. Then we see from the triangle inequality that

for all , which implies that

for some constants depending only on . In particular, we have

(compare with (1)). This motivates our first definition of Minkowski dimension:

Definition 1Let be a bounded subset of . Theupper Minkowski dimensionis defined asand the

lower Minkowski dimensionis defined asIf the upper and lower Minkowski dimensions match, we refer to as the Minkowski dimension of . In particular, the empty set has a Minkowski dimension of .

Unwrapping all the definitions, we have the following equivalent formulation, where is a bounded subset of and :

- We have , one has for
*all sufficiently small*and some . - We have , one has for
*arbitrarily small*and some . - We have iff for every , one has for
*arbitrarily small*and some . - We have iff for every , one has for
*all sufficiently small*and some .

- (i) Let be the Cantor set consisting of all base strings , where each takes values in . Show that has Minkowski dimension . (Hint: approximate any small by a negative power of .)
- (ii) Let be the Cantor set consisting of all base strings , where each takes values in when for some integer , and is arbitrary for the other values of . Show that has a lower Minkowski dimension of and an upper Minkowski dimension of .

Exercise 2Suppose that is a compact set with the property that there exist such that is equal to the union of disjoint translates of . (This is a special case of a self-similar fractal; the Cantor set is a typical example.) Show that has Minkowski dimension .If the translates of are allowed to overlap, establish the upper bound .

It is clear that we have the inequalities

for non-empty bounded , and the monotonicity properties

whenever are bounded sets. It is thus natural to extend the definitions of lower and upper Minkowski dimension to unbounded sets by defining

In particular, we easily verify that -dimensional subspaces of have Minkowski dimension .

Exercise 3Show that any subset of with lower Minkowski dimension less than has Lebesgue measure zero. In particular, any subset of positive Lebesgue measure must have full Minkowski dimension .

Now we turn to other formulations of Minkowski dimension. Given a bounded set and , we make the following definitions:

- (the
*external -covering number*of ) is the fewest number of open balls of radius with centres in needed to cover . - (the
*internal -covering number*of ) is the fewest number of open balls of radius with centres in needed to cover . - (the
*-metric entropy*) is the cardinality of the largest -net in , i.e. the largest set in such that for every . - (the
*-packing number*of ) is the largest number of disjoint open balls one can find of radius with centres in .

These three quantities are closely related to each other, and to the volumes :

Exercise 4For any bounded set and any , show thatand

As a consequence of this exercise, we see that

One can now take the formulae (4), (5) as the *definition* of Minkowski dimension for bounded sets (and then use (2), (3) to extend to unbounded sets). The formulations (4), (5) for have the advantage of being *intrinsic* – they only involve , rather than the ambient space . For metric spaces, one still has a partial analogue of Exercise 4, namely

As such, these formulations of Minkowski dimension extend without any difficulty to arbitrary bounded metric spaces (at least when the spaces are locally compact), and then to unbounded metric spaces by (2), (3).

Exercise 5If is a Lipschitz map between metric spaces, show that and for all . Conclude in particular that the graph of any Lipschitz function has Minkowski dimension , and the graph of any measurable function has Minkowski dimension at least .

Note however that the dimension of graphs can become larger than that of the base in the non-Lipschitz case:

Exercise 7Let be a bounded metric space. For each , let be a maximal -net of (thus the cardinality of is ). Show that for any continuous function and any , one has the inequality(

Hint:For any , define to be the nearest point in to , and use a telescoping series.) This inequality (and variants thereof), which replaces a continuous supremum of a function by a sum of discrete suprema of differences of that function, is the basis of thegeneric chainingtechnique in probability, used to estimate the supremum of a continuous family of random processes. It is particularly effective when combined with bounds on the metric entropy , which of course is closely related to the Minkowski dimension of , and withlarge deviationbounds on the differences . A good reference for generic chaining is the text by Talagrand.

Exercise 8If and are bounded sets, show thatand

Give a counterexample that shows that either of the inequalities here can be strict. (

Hint:There are many possible constructions; one of them is a modification of Exercise 1(ii).)

It is easy to see that Minkowski dimension reacts well to finite unions, and more precisely that

and

for any . However, it does not respect countable unions. For instance, the rationals have Minkowski dimension , despite being the countable union of points, which of course have Minkowski dimension . More generally, it is not difficult to see that any set has the same upper or lower Minkowski dimension as its topological closure , since both sets have the same -neighbourhoods. Thus we see that the notion of Minkowski dimension misses some of the fine structure of a set , in particular the presence of “holes” within the set. We now turn to the notion of Hausdorff dimension, which rectifies some of these defects.

** — 2. Hausdorff measure — **

The Hausdorff approach to dimension begins by noting that -dimensional objects in tend to have a meaningful -dimensional measure to assign to them. For instance, the -dimensional boundary of a polygon has a perimeter, the -dimensional vertices of that polygon have a cardinality, and the polygon itself has an area. So to define the notion of a -Hausdorff dimensional set, we will first define the notion of the -dimensional Hausdorff measure of a set .

To do this, let us quickly review one of the (many) constructions of -dimensional Lebesgue measure, which we are denoting here by . One way to build this measure is to work with half-open boxes in , which we assign a volume of . Given this notion of volume for boxes, we can then define the *outer Lebesgue measure* of any set by the formula

where the infimum ranges over all at most countable collections of boxes that cover . One easily verifies that is indeed an outer measure (i.e. it is monotone, countably subadditive, and assigns zero to the empty set). We then define a set to be *-measurable* if one has the additivity property

for all . By Carathéodory’s theorem, the space of -measurable sets is a -algebra, and outer Lebesgue measure is a countably additive measure on this -algebra, which we denote . Furthermore, one easily verifies that every box is -measurable, which soon implies that every Borel set is also; thus Lebesgue measure is a Borel measure (though it can of course measure some non-Borel sets also).

Finally, one needs to verify that the Lebesgue measure of a box is equal to its classical volume ; the above construction trivially gives but the converse is not as obvious. This is in fact a rather delicate matter, relying in particular on the completeness of the reals; if one replaced by the rationals , for instance, then all the above constructions go through but now boxes have Lebesgue measure zero (why?). See Chapter 1 of Folland’s book, for instance, for details.

Anyway, we can use this construction of Lebesgue measure as a model for building -dimensional Hausdorff measure. Instead of using half-open boxes as the building blocks, we will instead work with the open balls . For -dimensional measure, we will assign each ball a measure (cf. (1)). We can then define the *unlimited Hausdorff content* of a set by the formula

where the infimum ranges over all at most countable families of balls that cover . (Note that if is compact, then it would suffice to use finite coverings, since every open cover of has a finite subcover. But in general, for non-compact we must allow the use of infinitely many balls.)

As with Lebesgue measure, is easily seen to be an outer measure, and one could define the notion of a -measurable set on which Carathéodory’s theorem applies to build a countably additive measre. Unfortunately, a key problem arises: once is less than , most sets cease to be -measurable! We illustrate this in the one-dimensional case with and , and consider the problem of computing the unlimited Hausdorff content . On the one hand, this content is at most , since one can cover by the ball of radius centred at for any . On the other hand, the content is also at *least* . To see this, suppose we cover by a finite or countable family of balls (one can reduce to the finite case by compactness, though it isn’t necessary to do so here). The total one-dimensional Lebesgue measure of these balls must equal or exceed the Lebesgue measure of the entire interval , thus

From the inequality (which is obvious after expanding the RHS and discarding cross-terms) we see that

and the claim follows.

We now see some serious breakdown of additivity: for instance, the unlimited -dimensional content of is , despite being the disjoint union of and , which each have an unlimited content of . In particular, this shows that (for instance) is not measurable with respect to the unlimited content. The basic problem here is that the most efficient cover of a union such as for the purposes of unlimited -dimensional content is not coming from covers of the separate components and of that union, but is instead coming from one giant ball that covers directly.

To fix this, we will *limit* the Hausdorff content by working only with small balls. More precisely, for any , we define the Hausdorff content of a set by the formula

where the balls are now restricted to be less than or equal to in radius. This quantity is decreasing in , and we then define the *Hausdorff outer measure* by the formula

(This is analogous to the Riemann integral approach to volume of sets, covering them by balls, boxes, or rectangles of increasingly small size; this latter approach is also closely connected to the Minkowski dimension concept studied earlier. The key difference between the Lebesgue/Hausdorff approach and the Riemann/Minkowski approach is that in the former approach one allows the balls or boxes to be countable in number, and to be variable in size, whereas in the latter approach the cover is finite and uniform in size.)

Exercise 9Show that if , then for all . Thus -dimensional Hausdorff measure is only a non-trivial concept for subsets of in the regime .

Since each of the are outer measures, is also. But the key advantage of moving to the Hausdorff measure rather than Hausdorff content is that we obtain a lot more additivity. For instance:

Exercise 10Let be subsets of which have a non-zero separation, i.e. the quantity is strictly positive. Show that . (Hint:one inequality is easy. For the other, observe that any small ball can intersect or intersect , but not both.)

One consequence of this is that there is a large class of measurable sets:

Proposition 2Let . Then every Borel subset of is -measurable.

*Proof:* Since the collection of -measurable sets is a -algebra, it suffices to show the claim for closed sets . (It will be slightly more convenient technically to work with closed sets rather than open ones here.) Thus, we take an arbitrary set and seek to show that

We may assume that and are both finite, since the claim is obvious otherwise from monotonicity.

From Exercise 10 and the fact that is an outer measure, we already have

where is the -neighbourhood of . So it suffices to show that

For any , we have the telescoping sum , where , and thus by countable subadditivity and monotonicity

so it suffices to show that the sum is absolutely convergent.

Consider the even-indexed sets . These sets are separated from each other, so by many applications of Exercise 10 followed by monotonicity we have

for all , and thus is absolutely convergent. Similarly for , and the claim follows.

On the -measurable sets , we write for , thus is a Borel measure on . We now study what this measure looks like for various values of . The case is easy:

Exercise 11Show that every subset of is -measurable, and that is counting measure.

Now we look at the opposite case . It is easy to see that any Lebesgue-null set of has -dimensional Hausdorff measure zero (since it may be covered by balls of arbitrarily small total content). Thus -dimensional Hausdorff measure is absolutely continuous with respect to Lebesgue measure, and we thus have for some locally integrable function . As Hausdorff measure and Lebesgue measure are clearly translation-invariant, must also be translation-invariant and thus constant. We therefore have

for some constant .

We now compute what this constant is. If denotes the volume of the unit ball , then we have

for any at most countable collection of balls . Taking infima, we conclude that

and so .

In the opposite direction, observe from Exercise 4 that given any , one can cover the unit cube by at most balls of radius , where depends only on ; thus

and so ; in particular, is finite.

We can in fact compute explicitly (although knowing that is finite and non-zero already suffices for many applications):

Lemma 3We have , or in other words . (In particular, a ball has -dimensional Hausdorff measure .)

*Proof:* Let us consider the Hausdorff measure of the unit cube. By definition, for any one can find an such that

Observe (using Exercise 4) that we can find at least disjoint balls of radius inside the unit cube. We then observe that

On the other hand,

putting all this together, we obtain

which rearranges as

Since is bounded below by , we can then send and conclude that ; since we already showed , the claim follows.

Thus -dimensional Hausdorff measure is an explicit constant multiple of -dimensional Lebesgue measure. The same argument shows that for integers , the restriction of -dimensional Hausdorff measure to any -dimensional linear subspace (or affine subspace) is equal to the constant times -dimensional Lebesgue measure on . (This shows, by the way, that is not a -finite measure on in general, since one can partition into uncountably many -dimensional affine subspaces. In particular, it is *not* a Radon measure in general).

One can then compute -dimensional Hausdorff measure for other sets than subsets of -dimensional affine subspaces by changes of variable. For instance:

Exercise 12Let be an integer, let be an open subset of , and let be a smooth injective map which isnon-degeneratein the sense that the Hessian (which is a matrix) has full rank at every point of . For any compact subset of , establish the formulawhere the

Jacobianis the square root of the sum of squares of all the determinants of the minors of the matrix . (Hint:By working locally, one can assume that is the graph of some map from to , and so can be inverted by the projection function; by working even more locally, one can assume that the Jacobian is within an epsilon of being constant. The image of a small ball in then resembles a small ellipsoid in , and conversely the projection of a small ball in is a small ellipsoid in . Use some linear algebra and several variable calculus to relate the content of these ellipsoids to the radius of the ball.) It is possible to extend this formula to Lipschitz maps that are not necessarily injective, leading to thearea formulafor such maps, but we will not prove this formula here.

From this exercise we see that -dimensional Hausdorff measure does coincide to a large extent with the -dimensional notion of surface area; for instance, for a simple smooth curve with everywhere non-vanishing derivative, the measure of is equal to its classical length . One can also handle a certain amount of singularity (e.g. piecewise smooth non-degenerate curves rather than everywhere smooth non-degenerate curves) by exploiting the countable additivity of measure, or by using the area formula alluded to earlier.

Now we see how the Hausdorff dimension varies in .

Exercise 13Let , and let be a Borel set. Show that if is finite, then is zero; equivalently, if is positive, then is infinite.

Example 1Let be integers. The unit ball has a -dimensional Hausdorff measure of (by Lemma 3), and so it has zero -dimensional Hausdorff dimensional measure for and infinite -dimensional measure for .

On the other hand, we know from Exercise 11 that is positive for any non-empty set , and that for every . We conclude (from the least upper bound property of the reals) that for any Borel set , there exists a unique number in , called the *Hausdorff dimension* of , such that for all and for all . Note that at the critical dimension itself, we allow to be zero, finite, or infinite, and we shall shortly see in fact that all three possibilities can occur. By convention, we give the empty set a Hausdorff dimension of . One can also assign Hausdorff dimension to non-Borel sets, but we shall not do so to avoid some (very minor) technicalities.

Example 2The unit ball has Hausdorff dimension , as does itself. Note that the former set has finite -dimensional Hausdorff measure, while the latter has an infinite measure. More generally, any -dimensional smooth manifold in has Hausdorff dimension .

Exercise 14Show that the graph has Hausdorff dimension ; compare this with Exercise 6.

It is clear that Hausdorff dimension is monotone: if are Borel sets, then . Since Hausdorff measure is countably additive, it is also not hard to see that Hausdorff dimension interacts well with countable unions:

Thus for instance the rationals, being a countable union of -dimensional points, have Hausdorff dimension , in contrast to their Minkowski dimension of . On the other hand, we at least have an inequality between Hausdorff and Minkowski dimension:

Exercise 15For any Borel set , show that . (Hint: use (5). Which of the choices of is most convenient to use here?)

It is instructive to compare Hausdorff dimension and Minkowski dimension as follows.

Exercise 16Let be a bounded Borel subset of , and let .

- Show that if and only if, for every and arbitrarily small , one can cover by finitely many balls of radii equal to such that .
- Show that if and only if, for every and all sufficiently small , one can cover by finitely many balls of radii equal to such that .
- Show that if and only if, for every and , one can cover by countably many balls of radii at most such that .

The previous two exercises give ways to upper-bound the Hausdorff dimension; for instance, we see from Exercise 2 that self-similar fractals of the type in that exercise (i.e. is translates of ) have Hausdorff dimension at most . To lower bound the Hausdorff dimension of a set , one convenient way to do so is to find a measure with a certain “dimension” property (analogous to (1)) that assigns a positive mass to :

Exercise 17Let . A Borel measure on is said to be aFrostman measure of dimension at leastif it is compactly supported there exists a constant such that for all balls of radius has positive -dimensional Hausdorff content; in particular, .

Note that this gives an alternate way to justify the fact that smooth -dimensional manifolds have Hausdorff dimension , since on the one hand they have Minkowski dimension , and on the other hand they support a non-trivial -dimensional measure, namely Lebesgue measure.

Exercise 18Show that the Cantor set in Exercise 1(i) has Hausdorff dimension . More generally, establish the analogue of the first part of Exercise 2 for Hausdorff measure.

Exercise 19Construct a subset of of Hausdorff dimension that has zero Lebesgue measure. (Hint:A modified Cantor set, vaguely reminiscent of Exercise 1(ii), can work here.)

A useful fact is that Exercise 17 can be reversed:

Lemma 4 (Frostman’s lemma)Let , and let be a compact set with . Then there exists a non-trivial Frostman measure of dimension at least supported on (thus and ).

*Proof:* Without loss of generality we may place the compact set in the half-open unit cube . It is convenient to work dyadically. For each integer , we subdivide into half-open cubes of sidelength in the usual manner, and refer to such cubes as *dyadic cubes*. For each and any , we can define the *dyadic Hausdorff content* to be the quantity

where the range over all at most countable families of dyadic cubes of sidelength at most that cover . By covering cubes by balls and vice versa, it is not hard to see that

for some absolute constants depending only on . Thus, if we define the dyadic Hausdorff measure

then we see that the dyadic and non-dyadic Huausdorff measures are comparable:

In particular, the quantity is strictly positive.

Given any dyadic cube of length , define the upper Frostman content to be the quantity

Then . By covering by , we also have the bound

Finally, by the subadditivity property of Hausdorff content, if we decompose into cubes of sidelength , we have

The quantity behaves like a measure, but is subadditive rather than additive. Nevertheless, one can easily find another quantity to assign to each dyadic cube such that

and

for all dyadic cubes, and such that

whenever a dyadic cube is decomposed into sub-cubes of half the sidelength. Indeed, such a can be constructed by a greedy algorithms starting at the largest cube and working downward; we omit the details. One can then use this “measure” to integrate any continuous compactly supported function on (by approximating such a function by one which is constant on dyadic cubes of a certain scale), and so by the Riesz representation theorem, it extends to a Radon measure supported on . (One could also have used the Caratheódory extension theorem at this point.) Since , is non-trivial; since for all dyadic cubes , it is not hard to see that is a Frostman measure of dimension at least , as desired.

The study of Hausdorff dimension is then intimately tied to the study of the dimensional properties of various measures. We give some examples in the next few exercises.

Exercise 20Let , and let be a compact set. Show that if and only if, for every , there exists a probability Borel measure supported on withShow that this condition is also equivalent to lying in the Sobolev space . Thus we see a link here between Hausdorff dimension and Sobolev norms: the lower the dimension of a set, the rougher the measures that it can support, where the Sobolev scale is used to measure roughness.

Exercise 21Let be a compact subset of , and let be a Borel probability measure supported on . Let .

- Suppose that for every , every , and every subset of with , one could establish the bound for equal to any of (the exact choice of is irrelevant thanks to Exercise 4). Show that has Hausdorff dimension at least . (Hint: cover by small balls, then round the radius of each ball to the nearest power of . Now use countable additivity and the observation that sum is small when ranges over sufficiently small powers of .)
- Show that one can replace with in the previous statement. (Hint: instead of rounding the radius to the nearest power of , round instead to radii of the form for integers .) This trick of using a hyper-dyadic range of scales rather than a dyadic range of scales is due to Bourgain. The exponent in the double logarithm can be replaced by any other exponent strictly greater than .
This should be compared with the task of lower bounding the lower Minkowski dimension, which only requires control on the entropy of itself, rather than of large subsets of . The results of this exercise are exploited to establish lower bounds on the Hausdorff dimension of Kakeya sets (and in particular, to conclude such bounds from the Kakeya maximal function conjecture, as discussed in this previous post).

Exercise 22Let be a Borel set, and let be a locally Lipschitz map. Show that , and that if has zero -dimensional Hausdorff measure then so does .

Exercise 23Let be a smooth function, and let be a test function such that on the support of . Establish the co-area formula(Hint: Subdivide the support of to be small, and then apply a change of variables to make linear, e.g. .) This formula is in fact valid for all absolutely integrable and Lipschitz , but is difficult to prove for this level of generality, requiring a version of Sard’s theorem.

The coarea formula (6) can be used to link geometric inequalities to analytic ones. For instance, the sharp isoperimetric inequality

valid for bounded open sets in , can be combined with the coarea formula (with ) to give the sharp Sobolev inequality

for any test function , the main point being that is the boundary of (one also needs to do some manipulations relating the volume of those level sets to ). We omit the details.

Further discussion of Hausdorff dimension can be found in the books of Falconer, of Mattila and of Wolff, as well as in many other places.

## 55 comments

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20 May, 2009 at 3:52 am

Frank MorganOn infinite dimensional spaces, such as function spaces, there are many notions of small sets, such as category and measure 0, but the strongest is probably that of “positive codimension”; see B. White’s “Generic regularity of unoriented two-dimensional area minimizing surfaces,” MR MR794375.

20 May, 2009 at 3:59 am

Allen Knutson[In {K}-theory, it is also convenient to work with “virtual” vector spaces or vector bundles, such as formal differences of such spaces, and which may therefore have a negative dimension; but as far as I am aware there is no connection between this notion of dimension and the metric ones given here.]Interesting question. One way that those formal differences show up as honest dimensions is the following. If M is a topological space carrying a vector bundle V, and sigma is a generic section of V, then the dimension of sigma^{-1}(0) is dim M – dim V (where the second is the fiber dimension).

But for many purposes one may not want to take an actual section, e.g. because one doesn’t want to prejudice one over the other, or one may not have generic enough sections available because one’s working in a holomorphic context, or just because dim M – dim V would be negative (and so sigma^{-1}(0) would be empty). In such cases, rather than taking sigma^{-1}(0) as the object of interest, one should just keep around M and V, and declare the fibers to be odd vector bundles (in the supermanifold sense).

This point of view shows up (without mention of supermanifolds) in Fulton-MacPherson intersection theory, where the naive intersection M of two subvarieties is too big, and the correct intersection is represented by a vector bundle V over M, which may or may not have generic enough sections.

I don’t see any reason M can’t be a fractal. For these oddness purposes, I’m pretty sure V should be an actual vector bundle, not a bundle with fractal fibers.

Maybe you’d like this question. Let M,N be fractals, with dim M > dim N. Do “most” maps sigma from M -> N have the property that “most” fibers are fractals with dim = dim M – dim N? Add on whatever assumptions, e.g. compactness, you like.

20 May, 2009 at 8:37 am

Terence TaoMaybe you’d like this question. Let M,N be fractals, with dim M > dim N. Do “most” maps sigma from M -> N have the property that “most” fibers are fractals with dim = dim M – dim N? Add on whatever assumptions, e.g. compactness, you like.There are indeed results of this general flavour, though one often does have to assume various non-pathological assumptions, e.g. that various notions of dimension for M or N coincide. Here is a typical result (due to Marstrand, and later refined by Peres and Schlag, and stated somewhat informally): if is compact and has dimension d for some , then the image of E under "most" orthogonal projections has full dimension (and even positive measure). In fact the set of directions for which this statement fails has dimension at most . This isn't quite the type of thing you asked, but is in a similar spirit.

Incidentally, if one defines the complex Hausdorff dimension of a set to be half the real dimension, then there are some "algebraic" examples of fractals in complex geometry: the real m-dimensional manifolds become m/2-dimensional in this sense. In particular the real line is now a 1/2-dimensional complex fractal. I suppose one could try building a half-integer K-theory of real sections of complex vector bundles (maybe restricting to real algebraic varieties to avoid some pathologies); it would probably be a good model for any putative "fractal K-theory".

21 May, 2009 at 12:08 am

gowersWow, I’d never thought about this general idea of trying to unify fractal dimension and topological ideas in this sort of way, but once one starts thinking along these lines then there seem to be lots of possibilities. For instance, could one develop a notion of cohomology in which one could prove statements like that if and are suitable subsets of a -dimensional set, then as you deform them in some suitable way the cohomology class of in the group , where , does not change? And could one develop an infinitesimal boundary map (that is, one that reduces the dimension infinitesimally)? And in K-theory, could one have a continuous Bott periodicity theorem? Etc. etc. Do people think about this kind of question? And if so, is it generalization for the fun of it or is it conceivable that fractal algebraic topology could have applications?

21 May, 2009 at 12:20 am

VickyOn a rather less profound note, I think that n and d in the sentence including equation (1) should perhaps be the same.

[Corrected, thanks – T.]21 May, 2009 at 3:27 am

Frank MorganA simple remark on Terry’s question: in general the Hausdorff dimension of a product is greater than the sum of the Hausdorff dimensions of the factors (see http://en.wikipedia.org/wiki/Hausdorff_dimension).

21 May, 2009 at 9:09 am

Terence TaoDear Frank: Yes, to get a good theory (at least initially), one would have to exclude “pathological” sets (perhaps in analogy to how algebraic geometry works better when one only considers smooth varieties and transverse intersections; one can “fix” all these problems by passing to schemes, but I wouldn’t want to try to conjecture what a fractal scheme would look like yet). For instance, if one restricts attention to sets whose Hausdorff and Minkowski dimenion match, then one does recover the expected identity . Note that many standard examples of fractals, particularly self-similar fractals, do indeed have matching Hausdorff and Minkowski dimension. (It is also likely to help if one also assumes that the Hausdorff dimension matches some other useful notions of dimension as well, e.g. Fourier dimension.)

As I said before, perhaps an initial toy case would be that of trying to work out the cohomology or K-theory of smooth real manifolds or algebraic varieties inside complex manifolds (or complex vector bundles), as such “half-integer-dimensional complex fractals” are highly non-pathological in the analytic sense, even if they totally fail to have any complex structure. [Imagine for instance an alien race living in some complexified spacetime whose mathematicians had somehow managed to discover the complex numbers without ever learning about the real numbers, until they stumble upon some strange “fractal” objects in which we would recognise as real submanifolds, but which they are having a lot of difficulty understanding the geometry of with their purely complex methods. How would they begin to set up, say, the intersection theory of these objects?] But even here one has to be careful; intersection numbers of real manifolds, for instance, aren’t nearly as stable with respect to deformations as their complex counterparts (imagine perturbing two tangent circles, for instance). But presumably the real algebraic geometers have figured out all sorts of ways to deal with these sorts of issues, and perhaps some of those may extend to other well-behaved fractal settings. (For instance, one could start orienting these real manifolds to get signed intersections, but I have no idea how one would orient a more general fractal.)

In response to one of Tim’s questions, though, I would say that this would be a “generalization for the fun of it”, at least until something non-trivial gets discovered…

21 May, 2009 at 2:04 pm

studentDear Prof Tao,

is it possible to post your lectures in class to the web in the video lecture form?

some universities have opencourseware and they put some of their classes.

I think it would be perfect for the math community all over the world to watch your lectures online.

thanks

27 May, 2009 at 4:16 pm

AnonymousDear Prof. Tao,

It seems straightforward to generalize Hausdorff measure to non-Euclidean settings, say the p-adics, but are any such generalizations important?

More generally, I guess, what are some good applications of the study of Hausdorff dimension/measure to questions which do not seem at first to involve it? The Sobolev inequality you mentioned is a good example, but are there others? Maybe something connected in some way to Ratner’s theorems or dynamics/ergodic theory?

Thanks

29 May, 2009 at 7:47 am

Terence TaoDear anonymous,

I know that Hausdorff dimension plays a role in complex dynamics (indeed, many iconic examples of fractals, such as the Mandelbrot set, come from this field of mathematics), and also in random processes (Brownian motion, SLE, percolation, etc.), and have also made an appearance in other aspects of dynamical systems (e.g. Diophantine approximation), but I am not too familiar with these things. There is also a Hausdorff dimension-like notion for von Neumann algebras due to Voicolescu (though perhaps it is closer in some ways to Minkowski dimension) based on a non-commutative version of the metric entropy, but again I don’t know the details too well. As for the p-adics, I would imagine that metric methods such as Hausdorff dimension could theoretically be of use here, but the number-theoretic structure is much more powerful here than in the Euclidean setting and so the metric theory is likely to be overshadowed by the arithmetic one.

2 July, 2009 at 8:03 am

ConfusedSorry to ask but once in a while I happen to bump into both Hausdorff dimension and Hausdorff exponent in some papers on fractal and chaos. Is it the same thing?

Also curious, is the relations between Haudorff exponent and the power law exponent of the power spectrum is often confused with Hurst exponent… Does the Hausdorff exponent and the Hurst exponent define the same thing and meant the same thing?

21 July, 2010 at 4:30 am

Wolfgang M.There appear to be four typo’s between definition 1 and exercise 1: some d’s should be alpha’s. Thanks for the post!

[Corrected, thanks – T.]21 July, 2010 at 7:38 am

Wolfgang M.Thanks for making the changes; but now there are too many alpha’s in there! =)

[Oops, wasn’t paying enough attention. Fixed now – T.]22 September, 2010 at 9:07 am

SnegudDear prof. Tao,

There seems to be something wrong with second inequality in Exercise 4. If we take , and , then , and (we take ball with centre at )

[Corrected, thanks – T.]18 May, 2011 at 10:44 am

RainaDear Prof. Tao,

I have just started reading about Hausdorff dimensions.

Let S in n-dimensional Euclidean Plane be a compact set of Hausdorff dimension t where 0<t<n is a non-integer. Let S-epsilon be the union of epsilon neighborhoods of all points in S. I could imagine a relation between the Lebesgue measure of S-epsilon and Hausdorff measure of S. But I could not think clearly. Is there any relation?

Could you suggest me books for reference (to read in detail about relation between Hausdorff measures and other(Borel,probability,Lebesgue) measures)?

18 May, 2011 at 12:00 pm

Terence TaoYes. See Exercises 15 and 16 of the above post.

As for references, I can recommend the books of Falconer and of Mattila.

18 May, 2011 at 11:56 pm

RainaThanks sir..

3 February, 2012 at 12:33 am

RexTypo: “…the dyadic and non-dyadic Huausdorff measures are comparable”

[Corrected, thanks-T.]15 March, 2012 at 3:21 am

RainaIs there any Co-area formula involving non integer Hausdorff dimension?

Moreover is it sensible to write the following:

Let S be a subset in with Hausdorff dimension s and .

where is a uniformly s-dimensional measure.

22 July, 2012 at 10:19 am

hamsi kafalı temelprof tao I love you so much your real analysis notes are like a water in mohab desert

11 August, 2012 at 1:07 am

AnonymousSmall typo in the passage: “Let {0 \leq d \leq n}. Suppose {E} is a bounded portion of a {k}-dimensional subspace, e.g. {E = B^d(0,1) \times \{0\}^{n-d}}, where {B^d(0,1) \subset {\bf R}^d} is the unit ball in {{\bf R}^d} and we identify {{\bf R}^n} with {{\bf R}^d \times {\bf R}^{n-d}} in the usual manner.”

I believe the {k} here should be a {d}.

[Corrected, thanks – T.]11 August, 2012 at 1:08 am

RexWhoops. My login seems to have failed…

18 August, 2012 at 9:05 am

Lucas BrauneYou meant to write ‘prime’ instead of ‘maximal’ in the phrase “a chain of maximal ideals”.

[Corrected, thanks – T.]20 August, 2012 at 5:50 am

QuoraWhat are the basic differences between physical and mathematical dimensions? And what are some uses, applications or examples of mathematical dimensions in the physical world?…Terence Tao has a wonderful overview of the dimension concept [1]. Basically, there are several definitions of ‘dimension’ which we tend to use interchangeably because they give the same number in most cases. For instance determining the dimension by…

20 August, 2012 at 5:50 am

Dimensions: What are the basic differences between physical and mathematical dimensions? And what are some uses, applications or examples of mathematical dimensions in the physical world? - Quora[…] of fractals. The sierpinski triangle for instance, has dimension 1.58. [1] https://terrytao.wordpress.com/20…"},"cls:a.app.view.components:BlurredAnswer:MgVYc2IwuP1/dH",{}), […]

12 April, 2013 at 4:37 pm

John PearsonI believe that there are a couple of typos at the end of the proof of Lemma 3. At the end of the proof, I believe you should have

.

This allows you to conclude that which is what you want since you had shown in the lead-up to the lemma. (The inequalities were swapped in the version above.)

[Corrected, thanks – T.]20 May, 2014 at 4:27 pm

Sean EberhardDear Terry,

I’ve noticed that many sources define Hausdorff measure somewhat differently in that they allow coverings by arbitrary sets U and then take the sum of the contributions (diam U)^s. Is this an important difference? I think it makes showing n-dim Hausdorff measure = Lebesgue measure more difficult. Is there any effect on applications?

Actually, is there much in the way of applications at all, or is Hausdorff dimension more of an end than a means? A hypothetical application would be, say, an existence proof which proceeds by showing that the set of desired objects has positive dimension.

20 May, 2014 at 7:29 pm

Terence TaoThe two definitions of Hausdorff dimension are equivalent, because any set U can be covered by a ball of diameter comparable to that of U. I suppose one could use the other definition of Hausdorff dimension if one wished to downplay the role of metric balls.

As for applications, Hausdorff dimension is often equal to other notions of dimension for “non-pathological” sets; for instance, for real algebraic varieties, the real algebraic dimension is equal to the Hausdorff dimension. So one can often use results about Hausdorff dimension to say something about other notions of dimension.

One can also use Hausdorff dimension to extract some topological information. For instance, suppose one removes a closed set from . If all one knows about is that it has measure zero, then this can disconnect ; consider for instance removing a hyperplane from . But if one knows that has Hausdorff dimension strictly less than , one can show that the complement remains topologically path-connected (proof: given any two points in the complement, connect them by line segments to a randomly selected third point , and show that this almost surely avoids ). If has dimension strictly less than , then the complement is also simply connected, and so forth. Several years ago, I used these facts with Gang Tian to show some singularity removal theorems for Yang-Mills fields, by first bounding the Hausdorff dimension of the singular set, and then exploiting the topological triviality of the complement as a consequence.

11 June, 2014 at 6:49 am

ItayDear Prof. Tao,

I seem to be missing something. In the reformulation of upper and lower Minkowski dimension, it is not clear how does alpha play a role in the new formulation, and also maybe the volume should be the n-dimensional volume?

[Typos in post corrected, thanks – T.]4 February, 2015 at 5:27 am

priya jainIs there proof of exercise question????

21 March, 2015 at 5:08 pm

The Kakeya problem | Anurag's Math Blog[…] Kakeya sets in have Hausdorff dimension equal to […]

24 April, 2015 at 5:51 am

CyrilDear Terry;

I’ve been try to answer this question for a very long time:

What can on say about Hausdorff dimension of a subfield of $\mathbb{R}$ ?

I have already built a proper uncountable subfield of $\mathbb{R}$ with null Hausdorff dimension but I don’t know there exists such subfields with not null Haussdorff dimension. Have you got any idea ?

Thanks a lot for the quality of your blog and the time you spend to answer questions of such beginners as I am.

24 April, 2015 at 10:54 am

Terence TaoIn the case of Borel-measurable subfields, the Hausdorff dimension must be either 0 or 1, a result of Edgar and Miller (answering a question of Erdos and Volkmann): http://www.ams.org/mathscinet-getitem?mr=1948103 . There is a more technical quantitative version of this, due to Bourgain, which has a number of important applications such as in the theory of expander graphs (and most recently, in the Kakeya problem): http://www.ams.org/mathscinet-getitem?mr=1982147

I don’t know what happens if the hypothesis of Borel measurability is dropped; the question may be sensitive to the axioms of set theory in the ambient mathematical universe.

24 April, 2015 at 5:47 pm

Mark LewkoHi Terry,

I’m curious what the “most recent” application of Bourgain’s ring theorem to the Kakeya problem is. I know in some non-rigorous / heuristic sense Bourgain’s theorem should imply the KLT $5/2+\epsilon$ result (based on, say, the BKT finite field argument) but I am not familiar with any literature on this.

24 April, 2015 at 6:17 pm

Terence TaoThis is extremely recent work of Katz and Zahl, which should appear on the arXiv in a few weeks. As you guessed, it gives a Hausdorff dimension bound of for Kakeya sets via a Euclidean version of the BKT argument.

31 May, 2015 at 5:39 pm

Alan ChangI think there is a typo in the second paragraph of section 1 (“Minkowski dimension”), in particular, in this sentence:

“These are open sets in {{\bf R}^n} and therefore have a {d}-dimensional volume (or Lebesgue measure) {\hbox{vol}^d(E_\delta)}.”

Should the two {d}’s be {n}’s?

[Corrected, thanks -T.]15 April, 2016 at 2:06 am

245C, Notes 5: Hausdorff dimension (optional) | Alabair's Weblog[…] Source : 245C, Notes 5: Hausdorff dimension (optional) […]

11 May, 2016 at 7:46 pm

Anonymous2Does anybody happen to know where Minkowski gave his original work on “Minkowski dimension”?

12 May, 2016 at 5:47 pm

AnonymousIn Exercise 13, I think you mean ?

[Corrected, thanks – T.]29 May, 2016 at 1:27 pm

AnonymousBy Lemma 3, one can find the -dimension Hausdorff measure of an -dimensional ball . Do you have a hint how to find the (n-1)-dimension Hausdorff measure of the boundary ?

[Use Exercise 12 – T.]17 June, 2016 at 4:20 pm

AnonymousHi Terry,

I think in equations both (4) and (5), there should be “log” in the numerator as well.

[Corrected, thanks – T.]27 September, 2016 at 10:52 am

246A, Notes 2: complex integration | What's new[…] is clarified once one develops the theory of Hausdorff dimension, as is done for instance in this previous post: any curve of Hausdorff dimension strictly greater than one will be […]

19 April, 2017 at 11:05 pm

DominikThere is a typo in Lemma 4 (Frostman’s lemma). It should say “of dimension at most d” instead of “at least d”.

[Corrected, thanks – T.]21 April, 2017 at 1:02 am

DominikNow its wrong in both Lemma 4 and Exercise 17. It should say “at most d”.

22 April, 2017 at 4:05 am

DominikOk, now I see that it really should say “at least d”, because that’s what the condition in the definition of a Frostman measure means. So, it’s right now in Lemma 4 and Exercise 17, but still in the last line of the proof of Frostman’s lemma it says “at most d”.

[Corrected, thanks – T.]12 October, 2017 at 1:00 pm

AnonymousI think there are a few typos below definition 1

(e.g. the upper minkowski statement should have + \epsilon in it rather than a – \epsilon)

15 March, 2018 at 4:18 pm

The co-area formula exercise from Terry Tao’s blog | zulfahmed[…] is an exercise from Terry’s blog on Hausdorff […]

9 November, 2018 at 1:38 am

Fedor PetrovHow do we get the sigma-additivity of the measure obtained in the proof of Frostman’s lemma (on the semiring of dyadic cubes)? Does it require some additional care on the greedy procedure?

21 November, 2018 at 12:08 pm

Terence TaoThe measure provided by the Riesz representation theorem is automatically sigma-additive. (Alternatively one could also argue using the Kolmogorov extension theorem.)

13 January, 2019 at 7:30 am

AnonymousFor exercise 9, if , then

This shows that

ifthen ; this is weaker than the statement in Exercise 9. And it seems that the argument above does not exploit the special number yet. Can you give a hint?13 January, 2019 at 5:20 pm

Terence TaoFirst show that any bounded subset of has finite -dimensional Hausdorff outer measure.

13 January, 2019 at 8:40 pm

AnonymousLooks like Trick 6 in

https://terrytao.wordpress.com/2010/10/21/245a-problem-solving-strategies/

One can show this by covering the bounded subset of with balls of a smaller radius. It then follows by the observation in the previous comment that

for all bounded subsets. How to “patch things together”?

Without countably subadditive, how can one pass it to the unbounded case? (Stein-Shakarchi established subadditivity; one could look it up in the book. Can one do it alternatively?) Or does one have to establish some “continuity” of (which I don’t find a way to show) so that one can look at the Hausdorff outer measure of sets ?

(It’s interesting to look at different proofs. In Wolff’s notes that mentioned in the last sentence of this post, the author gave a mysterious one-sentence proof: “when , one can cover by discs with arbitrarily small.”, which I have no ideas what he means.)

14 January, 2019 at 8:41 am

Terence TaoUse Trick 11 (combined with Trick 2).

13 January, 2019 at 4:58 pm

ArashHi, “this quantity is increasing in $r$”. Should not it be decreasing with $r$?

[Corrected, thanks – T.]19 February, 2019 at 6:36 pm

AnonymousDear Prof. Tao,

In Exercise 20, the statement asserted to be equivalent to seems independent to the set . It may be better to correct this statement.

[Corrected, thanks – T.]